« McChesney, Jennings, Uncle Walter... American Journalism b. 17??- d. 1996-2005 | Main | FREAK SNOWSTORM IN HELL: Fat Charlie finds herself agreeing with George Will »
August 10, 2005
Calculus Equation #993
For this problem, you will need a calculator, possibly a protractor. Please see page 223 of the course syllabus.
We have four stated modes of existence, each with their own submodes. These are Republican (referred to for the rest of the problem R), Democrat (D), Conservative (C) and Liberal (L). These four modes can be paired off into twos, given the following conditions:
R can equal C, but never D
D can equal L, but never R
R sometimes equals L
D sometimes equals C
C and L can never equal each other
Give that in this paticular problem, R=C and D=L. (Henceforth will be referred to as RC and DL.) The combination of R and C can equal several possible outcomes: the Ten Commandments in your classroom, for example. In this paticular equation RC's outcome is a bleeting nasal sound and a book celebrating the life of JoeMcCarthy, (JoeMcCarthy=RC squared/paranoia + pumpkins.)
The combination of DL can equal several possible outcomes: a seemingly unstoppable streak of losing, for example. In this paticular equation DL's outcome is a wild hairdo and ability to march in a three-piece suit.
Your question is, which mode of existence, in this one equation, overpowers the other? You have ten minutes. You may use scratch paper if you need.
Posted by emily at August 10, 2005 6:04 PM
Comments
As C&L approach very large values, They serve as reasonable approximations of each other under most circumstances.
Posted by: Kyle at August 10, 2005 6:45 PM
Yes, but only as a single order approximation.
Posted by: triv ![[TypeKey Profile Page]](http://www.triv.org/fat-charlie/nav-commenters.gif)
at August 17, 2005 11:41 AM